x^2/5=5x-17

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Solution for x^2/5=5x-17 equation: 


x in (-oo:+oo)

(x^2)/5 = 5*x-17 // - 5*x-17

(x^2)/5-(5*x)+17 = 0

(x^2)/5-5*x+17 = 0

1/5*x^2-5*x+17 = 0

DELTA = (-5)^2-(1/5*4*17)

DELTA = 57/5

DELTA > 0

x = ((57/5)^(1/2)+5)/(1/5*2) or x = (5-(57/5)^(1/2))/(1/5*2)

x = 5/2*((57/5)^(1/2)+5) or x = 5/2*(5-(57/5)^(1/2))

x in { 5/2*(5-(57/5)^(1/2)), 5/2*((57/5)^(1/2)+5) }

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